mysql_query() ritorna questi valori:
Codice:
reject note Return Values
For SELECT, SHOW, DESCRIBE, EXPLAIN and other statements returning resultset, mysql_query() returns a resource on success, or FALSE on error.
For other type of SQL statements, INSERT, UPDATE, DELETE, DROP, etc, mysql_query() returns TRUE on success or FALSE on error.
The returned result resource should be passed to mysql_fetch_array(), and other functions for dealing with result tables, to access the returned data.
Use mysql_num_rows() to find out how many rows were returned for a SELECT statement or mysql_affected_rows() to find out how many rows were affected by a DELETE, INSERT, REPLACE, or UPDATE statement.
mysql_query() will also fail and return FALSE if the user does not have permission to access the table(s) referenced by the query.
nel tuo caso dato che è un INSERT, mysql_query() ritornerà true se la query viene eseguita correttamente, e false se la query non viene eseguita con il relativo errore.
quindi potresti fare così:
Codice PHP:
if (!test('blablabla')) die ('Errore query: '.mysql_error());