Raga ho recuperato da un vecchio post su AV il codice per il login del Forum alla Home.. ho creato la home con il link a una pagina : login.php
Nella login.php c'è il seguente codice..
mi da errore.. ki mi aiuta a scriverlo giusto??Codice:<?php $db_hostname = "localhost"; $db_username = "webhosting"; $db_password = "******"; $db_name = "my_webhosting"; $dbcon = mysql_connect($db_hostname, $db_username, $db_password); mysql_select_db("$db_name"); $login = " <p><span class="genmed"> <form action="phpBB2/login.php" method="post"> <input value="../index.php" name="redirect" type="hidden"> Username:<br /><input size="15" name="username" type="text" class="post"><br /> Password:<br /><input size="15" name="password" type="password" class="post"><br /> <br /> <input value="ON" name="autologin" type="hidden"> <input value="Login" name="login" class="mainoption" type="submit"></form><br /><br /> <a class="gensmall" href="phpBB2/profile.php?mode=sendpassword">Ho dimenticato la password</a><br /> <br /> Non hai ancora un account?<br /> Ti puoi <a href="phpBB2/profile.php?mode=register">registrare</a> gratuitamente</span> </span></p>n"; if (isset($HTTP_COOKIE_VARS[tfkbb2log_sid])) { $session_id = $HTTP_COOKIE_VARS[tfkbb2log_sid]; $query = "SELECT session_id, session_user_id, session_logged_in FROM bb_sessions WHERE session_id='$session_id'"; $result = mysql_query($query, $dbcon); $row = mysql_fetch_array($result); if ($session_id === $row[session_id]) { if ($row[session_logged_in] == "1") { $query2 = "SELECT username FROM bb_users WHERE user_id='$row[session_user_id]'"; $result2 = mysql_query($query2, $dbcon); $row2 = mysql_fetch_array($result2); echo "Benvenuto $row2[username]"; } else { echo $login; } } else { echo $login; } } else { echo $login; } ?>

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