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errore query
ciao a tutti!
Codice PHP:
<?php
mysql_query("SET CHARACTER SET utf8");
mysql_query("SET NAMES utf8");
$rowsPerPage = 20;
$pageNum = 1;
if (isset($_GET['page'])) {
$pageNum = $_GET['page'];
}
$offset = ($pageNum - 1) * $rowsPerPage;
$lettera=$_REQUEST['lettera'];
if ($lettera == NULL) {
$lettera = '';
} else {
$lettera=$_REQUEST['lettera'];
}
if ($spec == NULL and $lettera == NULL and $tipo_medico == 1) {
$Sqlqr_gl="select * from medici_chirurghi where cognome != '' order by IF (ASCII(LOWER(cognome)) >=ASCII (LOWER('$lettera')),1,2),cognome LIMIT $offset, $rowsPerPage";
$query="SELECT COUNT(m.id_albo) AS numrows from medici_chirurghi where cognome != ''";
} else if ($spec == NULL and $lettera != NULL and $tipo_medico == 1) {
$Sqlqr_gl="select * from medici_chirurghi where cognome != '' and cognome LIKE '$lettera%' order by cognome LIMIT $offset, $rowsPerPage";
$query="SELECT COUNT(m.id_albo) AS numrows from medici_chirurghi where cognome != '' and cognome LIKE '$lettera%'";
} else if ($spec != NULL and $tipo_medico == 1) {
$Sqlqr_gl="select m.* from medici_chirurghi m, matricola_specialita ms, specialita2 s where cognome != '' and s.id_spec = $spec and s.id_spec = ms.id_specialita and m.matricola2 = ms.matricola order by IF (ASCII(LOWER(cognome)) >=ASCII (LOWER('$lettera')),1,2),cognome LIMIT $offset, $rowsPerPage";
$query="SELECT COUNT(m.id_albo) AS numrows from medici_chirurghi m, matricola_specialita ms, specialita2 s where cognome != '' and s.id_spec = $spec and s.id_spec = ms.id_specialita and m.matricola2 = ms.matricola";
} else if ($spec == NULL and $lettera == NULL and $tipo_medico == 2) {
$Sqlqr_gl="select * from medici_odontoiatri where cognome != '' order by IF (ASCII(LOWER(cognome)) >=ASCII (LOWER('$lettera')),1,2),cognome LIMIT $offset, $rowsPerPage";
$query="SELECT COUNT(m.id_albo) AS numrows from medici_odontoiatri where cognome != ''";
} else if ($spec == NULL and $lettera != NULL and $tipo_medico == 2) {
$Sqlqr_gl="select * from medici_odontoiatri where cognome != '' and cognome LIKE '$lettera%' order by cognome LIMIT $offset, $rowsPerPage";
$query="SELECT COUNT(m.id_albo) AS numrows from medici_odontoiatri where cognome != '' and cognome LIKE '$lettera%'";
} else if ($spec != NULL and $tipo_medico == 2) {
$Sqlqr_gl="select m.* from medici_odontoiatri m, matricola_specialita ms, specialita2 s where cognome != '' and s.id_spec = $spec and s.id_spec = ms.id_specialita and m.matricola2 = ms.matricola order by IF (ASCII(LOWER(cognome)) >=ASCII (LOWER('$lettera')),1,2),cognome LIMIT $offset, $rowsPerPage";
$query="SELECT COUNT(m.id_albo) AS numrows from medici_odontoiatri m, matricola_specialita ms, specialita2 s where cognome != '' and s.id_spec = $spec and s.id_spec = ms.id_specialita and m.matricola2 = ms.matricola";
}
echo "<div style=display:none>".$Sqlqr_gl."</div>";
$qr_gl=mysql_query($Sqlqr_gl,$connessione)or die(mysql_error());
while($r_gl=mysql_fetch_array($qr_gl,MYSQL_ASSOC)) {
if ($r_gl['cognome'] != NULL) {
?>
Codice PHP:
<?php
if ($idmenu == '44') {
$tipo_medico = '2';
} else if ($idmenu == '45') {
$tipo_medico = '1';
}
$result=mysql_query($query) or die('Error, seconda query failed');
$row=mysql_fetch_array($result, MYSQL_ASSOC);
$numrows = $row['numrows'];
$maxPage = ceil($numrows/$rowsPerPage);
// print the link to access each page
$self = $_SERVER['PHP_SELF'];
$nav = '';
for($page = 1; $page <= $maxPage; $page++) {
if ($page == $pageNum) {
$nav .= "<strong><a href='#'>.$page.</a></strong>"; // no need to create a link to current page
} else {
$nav .= " <a href=\"$self?page=$page&idmenu=$idmenu&lettera=$lettera&spec=$spec&tipomedico=$tipo_medico\">.$page.</a> ";
}
}
if ($pageNum > 1) {
$page = $pageNum - 1;
$prev = " <a href=\"$self?page=$page&idmenu=$idmenu&lettera=$lettera&spec=$spec&tipomedico=$tipo_medico\"><</a> ";
$first = " <a href=\"$self?page=1&idmenu=$idmenu&lettera=$lettera&spec=$spec&tipomedico=$tipo_medico\">[First Page]</a> ";
} else {
$prev = ' '; // we're on page one, don't print previous link
$first = ' '; // nor the first page link
}
if ($pageNum < $maxPage) {
$page = $pageNum + 1;
$next = " <a href=\"$self?page=$page&idmenu=$idmenu&lettera=$lettera&spec=$spec&tipomedico=$tipo_medico\">></a> ";
$last = " <a href=\"$self?page=$maxPage&idmenu=$idmenu&lettera=$lettera&spec=$spec&tipomedico=$tipo_medico\">[Last Page]</a> ";
} else {
$next = ' '; // we're on the last page, don't print next link
$last = ' '; // nor the last page link
}
?>
l errore è : Error, seconda query failed
mi potreste dare una mano? grazie a tutti
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l errore è:
Unknown column 'm.id_albo' in 'field list'
grazie
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Da phpmyadmin m è una tabella e id_albo è una colonna? ps. lo so che ritorna i rows della/e colonna/e
